java中servlet处理页面的修改

2024-10-12 11:54:58

1、首先建立一个html文件，用来添加员工<!DOCTYPE html><html><head><m髫潋啜缅eta charset="UTF-8"><title>Insert title here</title></head><body><div>跳转地址以及提交方式<form action="addEmp" method="post"><fieldset> <legend>添加员工</legend> 姓名：<input type="text" name="name"><br> 年龄：<input type="text" name="age"><br> 薪水：<input type="text" name="sal"><br> <input type="submit" value="提交"><br> </fieldset></form></div></body></html>

3、public class AddEmp extends HttpServlet{继承Httpservlet类或者实现servlet接口protected void service(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {//web服务器的默认编码格式是iso-8859-1，为解决乱码问题，设置格式 request.setCharacterEncoding("utf-8");

5、 int age=Integer.parseInt(request.getParameter("age")); double sal=Double.parseDouble(request.getParameter("sal")); add(name,age,sal);//重定向，处理完逻辑后跳转路径 response.sendRedirect("listEmp");//out.println("添加成功！"); out.close();}